(3y^2-y-2)/(3y^2+5y+2)

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Solution for (3y^2-y-2)/(3y^2+5y+2) equation: 


D( y )

3*y^2+5*y+2 = 0

3*y^2+5*y+2 = 0

3*y^2+5*y+2 = 0

3*y^2+5*y+2 = 0

DELTA = 5^2-(2*3*4)

DELTA = 1

DELTA > 0

y = (1^(1/2)-5)/(2*3) or y = (-1^(1/2)-5)/(2*3)

y = -2/3 or y = -1

y in (-oo:-1) U (-1:-2/3) U (-2/3:+oo)

(3*y^2-y-2)/(3*y^2+5*y+2) = 0

3*y^2-y-2 = 0

3*y^2-y-2 = 0

DELTA = (-1)^2-(-2*3*4)

DELTA = 25

DELTA > 0

y = (25^(1/2)+1)/(2*3) or y = (1-25^(1/2))/(2*3)

y = 1 or y = -2/3

(y+2/3)*(y-1) = 0

3*y^2+5*y+2 = 0

3*y^2+5*y+2 = 0

DELTA = 5^2-(2*3*4)

DELTA = 1

DELTA > 0

y = (1^(1/2)-5)/(2*3) or y = (-1^(1/2)-5)/(2*3)

y = -2/3 or y = -1

(y+1)*(y+2/3) = 0

((y+2/3)*(y-1))/((y+1)*(y+2/3)) = 0

( y+2/3 )

y+2/3 = 0 // - 2/3

y = -2/3

( y-1 )

y-1 = 0 // + 1

y = 1

y in { -2/3} 

y = 1

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